0=-5t^2-4t-120

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Solution for 0=-5t^2-4t-120 equation: 



0=-5t^2-4t-120

We move all terms to the left:

0-(-5t^2-4t-120)=0

We add all the numbers together, and all the variables

-(-5t^2-4t-120)=0

We get rid of parentheses

5t^2+4t+120=0

a = 5; b = 4; c = +120;
Δ = b2-4ac
Δ = 42-4·5·120
Δ = -2384
Delta is less than zero, so there is no solution for the equation

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